The actual 'voltage supply' from the battery is 12 volts; while the USB plugs themselves take in that 12v
input & cut their
output down to a MAXIMUM of
5 volts @ 2.1 amps; but I
think you might be asking the wrong question. You really want to know the maximum amperage your phone can be charged at, or maybe that should be the maximum wattage?! Someone who's more versed in this stuff than my thorough cursory understanding can handle might be able to explain it all better, but here goes...
Voltage is a measurement of the electric potential or "pressure" (current?!) at which electricity flows through a system, or if you like, the speed the electrons can travel thru the circuit; while
Amperage is the "rate" that current is flowing through the circuit, or
the number of electrons moving through the wiring; and
Wattage is the
amount of power an electric device consumes - another way to think about wattage is "electricity at work" or the power it takes to actually do something... I take it that you really don't want to push
too much wattage into your phone?! :dontknow:
To calculate wattage, you simply multiply voltage (pressure/speed) by amperage (volume) - V x A = W. The faster each electron moves through the circuit (voltage), and the greater the volume that the circuit can hold (amperage), the higher the wattage. :thumbup:
So if as I take it is the case, you really don't want to fry your phone, then that means you want to know the max wattage it can handle. Your phone will have an ideal charging wattage on it/in its' specs somewhere, usually expressed as something like 5.0v~2.1a =
10.5w, and
THAT is what's important for your phone, which should tie in nicely with the max 5.0v~2.1a output from those USB plugs...

hyea:
I'm happy for someone else to correct my explanation/have a better go at presenting/understanding it; but if I've read what you're concerned about correctly, the 12v battery voltage never actually gets to the output side of the USB plugs, because they are specifically designed and engineered to only provide/allow sufficient power output to charge things like phones without frying them -
their max output is only 5v & 2.1a, so V x A = 5 x 2.1, resulting in 10.2w MAX. :thumbup:
Make sense??
